8.8 Review Questions
- Determine whether the following interpretations of a 95% confidence interval (337, 343) ml for the population mean volume of beer [latex]\mu[/latex] are true or false. If false, correct it.
- We can be 95% confident that [latex]\mu[/latex] is somewhere between 337 ml and 343 ml.
- We can be 95% confident that the sample mean [latex]\bar x[/latex] is somewhere between 337 and 343 ml.
- The probability that the population mean [latex]\mu[/latex] is within the interval (337, 343) is 0.95.
- The probability that the sample mean [latex]\bar x[/latex] is within the interval (337, 343) is 0.95.
- 95% of the [latex]\bar x[/latex] values are within the interval (337, 343).
- Determine whether the following statements about the [latex]P[/latex]-value are true or false. If false, correct it.
- We should reject the null hypothesis [latex]H_0[/latex] if the [latex]P[/latex]-value[latex]\le \alpha[/latex].
- We should accept the null [latex]H_0[/latex] if the [latex]P[/latex]-value[latex]> \alpha[/latex].
- [latex]P[/latex]-value is the probability that the null [latex]H_0[/latex] is true.
- [latex]P[/latex]-value is the probability of rejecting [latex]H_0[/latex].
- Suppose you perform a statistical test to decide whether a nuclear reactor should be approved. Further, suppose that failing to reject the null hypothesis (the reactor is safe to use) corresponds to approval.
- Write down the null and alternative hypotheses.
- What are the type I and type II errors in this example?
- Which error has more serious consequence, type I or type II? Would you like to set [latex]\alpha[/latex] or [latex]\beta[/latex] to be relatively small?
- The mean retail price of agriculture books in 2005 was $57.61. This year’s retail mean price for 28 randomly selected agriculture books was $54.97. Assume that the population standard deviation of prices for this year’s agriculture books is $8.45.
- At the 10% significance level, do the data provide sufficient evidence to conclude that this year’s mean retail price of agriculture books has changed from the 2005 mean?
- What is the [latex]P[/latex]-value of the test in part (a)?
- Obtain a confidence interval corresponding to the test in part (a).
- Does the interval obtained in part (c) support the result in part (a)?
- The ankle brachial index (ABI) compares the blood pressure of a patient’s arm to the blood pressure of the patient’s leg. The ABI can be an indicator of different diseases, including arterial diseases. A healthy (or normal) ABI is 0.9 or greater. Researchers obtained the ABI of 100 women with peripheral arterial disease and obtained a mean ABI of 0.64 with a standard deviation of 0.15.
- At the 5% significance level, do the data provide sufficient evidence that, on average, women with peripheral arterial disease have an unhealthy ABI?
- What is the [latex]P[/latex]-value of the test in part (a)?
- Obtain a confidence interval corresponding to the test in part (a).
- Does the interval obtained in part (c) support the conclusion in part (a)?
Show/Hide Answer
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- True, a standard way to interpret the confidence interval.
- False. The sample mean [latex]\bar{x}[/latex] is the center of the interval; we should be 100% confident that the sample mean [latex]\bar{x}[/latex] is in the interval.
- False. There is no randomness here and hence there is no probability, since the population mean [latex]\mu[/latex] is a constant and the interval (337, 343) is also fixed. [latex]\mu[/latex] is either within the interval or outside the interval.
- False. Similar arguments as the previous. The sample mean [latex]\bar{\mu}[/latex] is a fixed number, and the interval is also fixed; there is no randomness.
- False. 95% of the [latex]\bar{\mu}[/latex] values are within the interval [latex]( \mu - 1.96 \frac{\sigma}{\sqrt{n}}, \mu + 1.96 \frac{\sigma}{\sqrt{n}} ).[/latex]
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- True.
- False. In general, never accept [latex]H_0[/latex].
- False. P-value measures the strength of the evidence that the data contradicts [latex]H_0[/latex] and is in favour of [latex]H_a[/latex].
- False. P-value is the probability of observing [latex]z_0 (t_0)[/latex] or more extreme values.
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- [latex]H_0[/latex]: the nuclear reactor is safe versus [latex]H_a[/latex]: the nuclear reactor is not safe.
- Type I error: disapprove of the nuclear reactor of ruse given that the nuclear reactor is actually safe.
Type II error: approve the nuclear reactor for use given that the nuclear reactor is not safe. - Type II error is more severe than type I. We probably need to set the type II error rate relatively small.
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- Assumptions:
We have a simple random sample.
We have a large sample with [latex]n=100 >30.[/latex]
Population standard deviation [latex]\sigma[/latex] is unknown.
We can use a one-sample t-test. Summarize the information: [latex]n =100, \bar{x} = 0.64, s= 0.15[/latex]. The six steps to perform a one-sample t-test are:- Hypotheses: [latex]H_0: \mu \ge 0.9 \text{ versus } H_a : \mu < 0.9.[/latex]
- The significance level [latex]\alpha = 0.05.[/latex]
- Observed test statistic:
[latex]t_o = \frac{\bar{x} - \mu_0}{s / \sqrt{n}} = \frac{0.64 - 0.9}{ 0.15 / \sqrt{100}} = -17,333[/latex]
with [latex]df = n -1 = 99.[/latex] - A left-tailed test, P-value = [latex]P( t \le t_0 ) = P(t \le -17.333 ) = P(t \ge 17.333 ) < 0.005[/latex].
- Since P-value < 0.005 < 0.05[latex](\alpha)[/latex], we reject [latex]H_0[/latex].
- At the 5% significance level, we have sufficient evidence that, on average, women with peripheral arterial disease have an unhealthy ABI
- P-value < 0.005
- A left-tailed test at significance level [latex]\alpha = 0.05[/latex] corresponds to a [latex]( 1- \alpha ) \times 100%[/latex] lower-tailed confidence interval. With df = 99 not given in Table IV, use df = 90 the closed one but still no more than 99, [latex]\alpha =0.05 \Longrightarrow t_{\alpha} = t_{0.05} = 1.662[/latex]
[latex](-\infty, \bar{x} + t_{\alpha} \frac{s}{\sqrt{n}} ) = ( -\infty, 0.64 + 1.662 \times \frac{0.15}{\sqrt{100}} ) = (-\infty, 0.665).[/latex]
Interpretation: we can be 95% confident that the mean ABI of women with peripheral arterial disease is somewhere below 0.665.
Note: In this course, you are only required to know how to obtain a two-tailed interval. For df=99 (use 90), [latex]t_{\alpha / 2} = t_{0.025} = 1.987[/latex]. The 95% two-tailed interval is
[latex]\bar{x} \pm t_{\alpha/2}\frac{s}{\sqrt{n}} = 0.64 \pm 1.987 \times \frac{0.15}{\sqrt{100}} = (0.610, 0.670).[/latex]
Interpretation: we can be 95% confident that the mean ABI of women with peripheral arterial disease is somewhere between 0.610 and 0.670. The entire interval is below 0.9, so we can claim [latex]\mu < 0.9.[/latex] - Yes, since a healthy (or normal) ABI is 0.9 or greater; however, 0.9 is outside the confidence interval (it is above the entire interval), so we can claim that the mean ABI of women with peripheral arterial disease is below 0.9, i.e., [latex]\mu < 0.9[/latex]. This is consistent with the conclusion of the t-test in part a).
- Assumptions: